inverses
solve for x
replace x with f inverse
replace y with x
so
first minus 2 both sides
y-2=√(2x-3)
square both sides
y^2-4y+4=2x-3
add 3 to both sides
y^2-4y+7=2x
divide both sides y 2
(y^2-4y+7)/2=x
x turns to f inverse and y turns to x
f(x)⁻¹=\(\frac{x^{2}-4x+7}{2}\)
looks like they didn't want to expand the binomial
y=\(\frac{(x-2)^{2}}+3}{2}\)
answer si A
