factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm
we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=\(\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}\)
0=x^2+12x+16
a=1
b=12
c=16
x=\(\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}\)
x=\(\frac{-12+/- \sqrt{144-64 }}{2}\)
x=\(\frac{-12+/- \sqrt{80}}{2}\)
x=\(\frac{-12+/- 4\sqrt{5}}{2}\)
x=\(\frac{-6+/- 2\sqrt{5}\)
x=\(\frac{-6+ 2\sqrt{5}\) or \(\frac{-6- 2\sqrt{5}\)
aprox
x=-1.52786 or -10.4721
those are the numbers
the numbes are -1.52786 or -10.4721
