Explanation:
The given reaction equation is as follows.
\(^{14}_{7}N\) + ___ \(\rightarrow ^{14}_{6}C + ^{1}_{1}H\)
As there is release of one hydrogen which shows that mass number has increase by 1 on the product side.
Therefore, particle \(^{1}_{0}n\) must be added in order to balance the given reaction equation.
Hence, the complete reaction equation will be as follows.
\(^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H\)
