solve
set to zero by minusing 6 both sides
x^2+4x-2=0
we can't factor
ok so use quadratic formula
ax^2+bx+c=0
x=\(\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}\)
a=1
b=4
c=-2
x=\(\frac{-4+/- \sqrt{4^{2}-4(1)(-2)} }{2(1)}\)
x=\(\frac{-4+/- \sqrt{16+8} }{2}\)
x=\(\frac{-4+/- \sqrt{24} }{2}\)
x=\(\frac{-4+/- 2\sqrt{6} }{2}\)
x=\(-2+/- \sqrt{6}\)
x=\(-2+ \sqrt{6}\) or \(-2- \sqrt{6}\)
answer is A and C
