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The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration

Verified Answer :

The acceleration of the ball would be around 9.1666667m/s
To work this out use this formula 

acceleration = distancevelocity/distancetime

Answer:The magnitude of the acceleration is \(9.70 m/s^2\)

Explanation:

Final velocity of the ball falling down ,v = 33 m/s

Initial velocity of the ball ,u= o m/s

Time taken by the ball to reach the ground ,t = 3.4 seconds

Acceleration of the ball during the fall = a

Using first equation of motion:

\(v=u+at\)

\(33 m/s=0 m/s+a(3.4 s)\)

\(a=\frac{33 m/s}{3.4 s}=9.70 m/s^2\)

The magnitude of the acceleration is \(9.70 m/s^2\)

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