Verified Answer :

TSO

\(2x^4(4x^2 + 3x + 1)=\\\\(2x^4)(4x^2)+(2x^4)(3x)+(2x^4)(1)=\\\\8x^6 + 6x^5+2x^4\)

The answer isĀ A.

Answer:

The product of the \(2x^{4}(4x^{2}+3x+1)\) is \(8x^{6}+6x^{5}+2x^{4}\) .

Step-by-step explanation:

As given the expression in the question be

\(= 2x^{4}(4x^{2}+3x+1)\)

First open the bracket

\(= 2x^{4}\times 4x^{2}+2x^{4}\times 3x+2x^{4}\times 1\)

Now by using the property

\(x^{a}\times x^{b}=x^{a+b}\)

\(= 8x^{6}+6x^{5}+2x^{4}\)

Therefore the product of the \(2x^{4}(4x^{2}+3x+1)\) is \(8x^{6}+6x^{5}+2x^{4}\) .