Verified Answer :

meerkat18

h(x) = 3x - 1
j(x) = -2x

h[j(2)] ⇒ j(2) = -2(2) ⇒ j(2) = -4

h(-4) = 3(-4) - 1
h(-4) = -12 - 1
h(-4) = -13

h[j(2)] = -13

Answer:

Option 3rd is correct.

the value of h[j(2)]  is, -13

Step-by-step explanation:

Given the functions:

\(h(x) = 3x-1\)

\(j(x) = -2x\)

We have to find the value of  h[j(2)]

\(h[j(x)] = h[-2x]\)

Replace x from -2x in h(x) we have;

\(h[-2x] = 3(-2x)-1 = -6x -1\)

⇒\(h[j(x)] = -6x-1\)

Substitute the value of x = 2 we get;

\(h[j(2)] = -6(2)-1 = -12-1 = -13\)

Therefore, the value of h[j(2)]  is, -13

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