- What is the length of the altitude CD in the figure?O A. 2.7B. 2.2C. 3.9O D. 3.3BackNext
We have a right triangle:
hypotenuse=6
leg₁=5
leg₂=CD
Pythagoras theorem:
hypotenuse²=leg₁²+leg₂²
6²=5²+CD²
CD=√(6²-5²)
CD=√(36-25)
CD=√11≈3.3166....≈3.3
Answer: D. 3.3
Answer:
The length of the altitude CD is 3.3 units .
Option (D) is correct .
Step-by-step explanation:
By using the pythagorean theorem
Hypotenuse² = Perpendicular² + Base²
Now in ΔCDA
Hypotenuse = CA = 6 unit
Base = AD = 5 units
Perpendicular = CD
Put all the values in the above
6² = CD² + 5²
As
6² = 36
5² = 25
CD² = 6² - 5²
= 36 - 25
CD² = 11
\(CD = \sqrt{11}\)
CD = 3.3 unit (Approx)
Therefore the length of the altitude CD is 3.3 units .
Option (D) is correct .