How much Sr(OH)2 • 8 H2O (M = 265.76) is needed to prepare 250.0 ML of solution in which [OH]= 0.100M?
Use the formula
first step:
Use the formula
molarity= mole/liter
change ml to l
plug in data
to get .1=mole/.25 or .1M.25liter
which =.025 moles
then divide .025 moles by two because there are two OH in Sr(OH)2
then multiply that by 265.76 (the molar mass of water)
.0125265.76
which is 3.32grams this is your answer
The answer is = 3.322grams
The explanation:
1-First we need o get the no.of moles:
moles = molarity volume(L)
by substitution:
∴ moles = 0.1M 0.25 L
= 0.025 moles
but we have 2 OH in Sr(OH)2
so moles = 0.025 /2 = 0.0125 moles
2- then we need to get how many grams of it so, we are going to use this formula:
mass = moles molar mass
by substitution:
∴ mass = 0.0125 265.76
= 3.322 grams