the zeros of the function f (x)=(x+2)^2-25
diffrence of 2 perfect squraesa^2-b^2=(a-b)(a+b)(x+2)^2-(5)^2=(x+2-5)(x+2+5)=(x-3)(x+7)set to zerox-3=0x=3x+7=0x=-7zeoes are x=3 and -7