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Seventy-five times a negative integer minus 36 equals 21 times the square of the negative integer. Which equation could be used to solve for the unknown negative integer?

Verified Answer :

lime52

-75x - 36 = -21x²

-75x   Seventy-five times a negative integer
-36   Minus 36
=   Equals
-21x²   The square of the negative integer

Hope this helps!

Answer:

\(21 x^2 +75 x+36 =0\)

Step-by-step explanation:

Let us assume that the negative integer is  -x

Now we have

Seventy - five times a negative integer = \(75 (-x ) = -75 x\)

Seventy - five times a negative integer minus 36 = \(-75x - 36\)

Square of negative integer = \((-x)^2 = x^2\)

21 times the square of negative integer = \(21 x^2\)

Now it is given that

Seventy - five times a negative integer minus 36  is equal to 21 times the square of negative integer

So we have

\(-75x -36 = 21 x^2\)

We can also try to write this in standard form by bring all the terms to one side

\(-75x = 21 x^2 +36\)  ( adding 36 to both sides)

\(0 = 21 x^2 +75 x+ 36\)  ( adding 75x to both sides )

\(21 x^2 +75 x+36 =0\)  ( Answer )

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