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A compound has the formula CH3CO2H.r How should the relative molecular mass, Mr, of this compound be calculated?A 12 1 16B 3(12 1) 2(12 16) 1C (4 x 12) (2 x 1) 16D (2 x 12) (4 x 1) (2 x 16)

A compound has the formula CH3CO2H.r How should the relative molecular mass, Mr, of this compound be calculated?A 12 1 16B 3(12 1) 2(12 16) 1C (4 x 12) (2 x 1) class=

Verified Answer :

Carbon has a Molar Mass of 12, Hydrogen has a Molar Mass of 1 and Oxygen has a Molar Mass of 16.

Acetic Acid has 2 Carbon atoms, 4 Hydrogen atoms and 2 Oxygen atoms.
Therefore, to calculate relative molecular mass all we need to do is:

212 + 41 + 2*16 = 60 g/mol

Lanuel

The relative molecular mass (Mr) of the compound (\(CH_3CO_2H\)) should be calculated as: D. (2 x 12) + (4 x 1) + (2 x 16).

Relative molecular mass can be defined as the total sum of all the relative atomic masses of atoms contained in a chemical compound.

We can deduce the following information from this compound (\(CH_3CO_2H\)):

Carbon = 2 atoms = \(2 \times 12 = 24\)

Hydrogen = 4 atoms = \(4 \times 1 = 4\)

Oxygen = 2 atoms = \(2 \times 16= 32\)

Relative molecular mass (\(CH_3CO_2H\)) = \(24+ 4+ 32 = 60\)

Note:

  • The relative atomic weight of carbon = 12 u
  • The relative atomic weight of hydrogen = 1 u
  • The relative atomic weight of oxygen = 16 u

In conclusion, the relative molecular mass (Mr) of the compound (\(CH_3CO_2H\)) should be calculated as \((2 \times 12) + (4 \times 1) + (2 \times 16)\)

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