Answer:
Option C is the correct option.
Step-by-step explanation:
The given equation is 2x² - 7x - 3 = 0
In this quadratic equation we will use quadratic formula to get the roots of x.
\(x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}\)
By putting values of a = 2, b = -7 and c = -3 in the quadratic formula
\(x=\frac{7\pm \sqrt{(-7)^{2}-4\times 2\times (-3)}}{2\times 2}\)
\(=\frac{7\pm \sqrt{49+24}}{4}\)
\(=\frac{7\pm \sqrt{73}}{4}\)
Now we get two values for x
\(x=\frac{7+\sqrt{73}}{4}\)
\(=\frac{7+8.54}{4}=3.89\)
and \(x=\frac{7-\sqrt{73}}{4}\)
\(=\frac{7-8.54}{4}\)
\(=-\frac{1.54}{4}=-0.39\)
Therefore option C. is the answer.
