Verified Answer :

SmarticalParticals

Both 3 and x are common to all of the expressions so we can factor them out...

3x^3 - 3x^2 -18x
3x (x^2 -x -6)

Now factor inside the parentheses

3x(x - 3)(x + 2)

Done.  Answer C (or the 3rd one down)

boffeemadrid

Answer:

(C)\(3x(x-3)(x+2)\)

Step-by-step explanation:

The given equation is:

\(3x^3-3x^2-18x\)

Upon solving this equation, we get

Taking 3x common from all the terms of the above equation,

\(3x(x^2-x-6)\)

Now, factorizing the above equation, we have

\(3x(x^2-3x+2x-6)\)

\(3x(x(x-3)+2(x-3))\)

\(3x(x-3)(x+2)\)

which is the required factorized form of the above equation.

Hence, option C is correct.

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