A tire is a circle, therefore:
1) we have to calculate the circumference of this circle (tire of this bycicle)
C=dπ
diameter=20 in
C=20π in.
1 rotation=20π in
2)we convert 500 ft to in
1 foot=12 in;
1 foot------------------12 in
500 feet--------------- x
x=(500 ft 12 in) / 1 foot=6000 in.
3) Now, we calculate the number of rotations:
1 rotation=20π in≈203.141592654... in≈62.93 in,
1 rotation--------------62.93 in
x--------------------------6000 in
x=(1 rotatiton * 6000 in) / 62.93 in≈95.5 rotations≈96 rotations.
Answer: 96 rotations.
