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. In fruit flies, normal wings are dominant and short wings are recessive. Construct a Punnett square wherein both parents are heterozygous for normal wings. Which of the following is the correct genotypic ratio for the F1 generation of this cross?


25% of the offspring are homozygous for normal wings. 50% of the offspring are heterozygous for normal wings. 25% of the offspring are homozygous recessive for short wings.

75% of the offspring have normal wings, and 25% of the offspring have short wings.

50% of the offspring are heterozygous for normal wings. 50% of the offspring are homozygous recessive for short wings.

75% of the offspring are heterozygous for normal wings. 25% of the offspring are homozygous recessive for short wings.

Verified Answer :

Normal wings = WW
Short wings = ww

The Parents = Ww x Ww

A. 25% are homozygous dominate, 50% are heterozygous, 25% are homozygous recessive.

Answer:

25% of the offspring are homozygous for normal wings. 50% of the offspring are heterozygous for normal wings. 25% of the offspring are homozygous recessive for short wings.

Explanation:

Let dominant allele be A and recessive allele be a

Parent 1: heterozygous normal wings = Aa

Parent 2: heterozygous normal wings = Aa

Parent 1 X Parent 2 :

     A       a

A   AA    Aa

a    Aa    aa

Genotype of progeny will be as follows:

1/4 or 25% = AA = homozygous dominant for normal wings

1/2 or 50% = Aa = heterozygous normal wings

1/4 or 25% = aa = homozygous recessive for short wings

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