Answer:
The mean absolute deviation of first data is \(2.54\)
and for second data is \(2.115\)
Step-by-step explanation:
Mean of data \(x_1,x_2,x_3,x_4,...x_{n}\) is calculated as:
\(mean=\frac{x_1+x_2+x_3+x_4+...+x_n}{n}\)
and mean absolute deviation is calculated as \(\sqrt{mean}\)
The given first data : 10 7 1 6 7 9 8 10 2 5
\(mean=\frac{x_1+x_2+x_3+x_4+...+x_n}{n}\)
\(mean=\frac{10+7+1+6+7+9+8+10+2+5}{10}\)
\(mean=6.5\)
mean absolute deviation \(\sqrt{6.5}=2.54\)
The given first data : 2 2.4 6.5 7
\(mean=\frac{x_1+x_2+x_3+x_4+...+x_n}{n}\)
\(mean=\frac{2+2.4+6.5+7}{4}\)
\(mean=\frac{17.9}{4}\)
\(mean=4.475\)
mean absolute deviation \(\sqrt{4.475}=2.115\)
Therefore, the mean absolute deviation of first data is \(2.54\)
and for second data is \(2.115\)
