In

May, Liam and Charlie had the same amount of money in their savings

accounts. In June, Liam deposited $140 into his account. Charlie said he

increased the money in his account by 5%. When they compared their

balances, they found that they were still equal.

How much money did they both have in their accounts in May?

Liam’s saving = x + $140

Charlie’s saving = x + 5%

In order to get the value of x, let’s find the amount which 5% is equals to 140

=> 2800

=> 5% = 0.05

=> 2800 x 0.05

=> 140

=> 2800 (amount that Liam and Charlie have in their account before they
added)

Thus, Liam and Charlie both have $2800 on their account .

=> Liams = 2800 + 140 = 2940

=> Charlir = 2800 + 5% (140) = 2940.

Answer Link

calculista calculista · Answer 2 · 2018-08-01T11:57:26-04:00

Let

x-------> amount of money in their savings
accounts in May

we know that

In June, Liam deposited $@@MATH_TOKEN_0@@ into his account

so

Balance Liam’s saving in June is equal to

@@MATH_TOKEN_1@@ ------> equation @@MATH_TOKEN_2@@

In June, Charlie increased the money in his account by@@MATH_TOKEN_3@@%

Balance Charlie’s saving in June is equal to

@@MATH_TOKEN_4@@ ------> equation @@MATH_TOKEN_5@@

Equate equation @@MATH_TOKEN_6@@ and equation @@MATH_TOKEN_7@@

@@MATH_TOKEN_8@@$

therefore

the answer is

$$2,800$