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A weather balloon at Earth’s surface has a volume of 3.9 L at 299 K and 763 mmHg. If the balloon is released and the volume reaches 4.13 L at 720 mmHg, what is the temperature? Answer in units of K.

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Combined Gas Laws

Given: V1= 3.9L    V2= 4.13L   T1= 299K   P1=763mmHg   P2=720mmHg

Unknown: T2=?

Formula: T2=T1P2V2 / P1V1

Solution: T2= (299K)(720mmHg)(4.13L) / (763mmHg)(3.9L)
                   = 889,106.4 / 2975.7

Answer: T2=298.8K

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