Verified Answer :

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(%m/v) =mass of solute (in g) / volume of solution (in mL) x 100
       
            = 952 g (NH4)2CO3 / 1750 mL x 100
    
            = 0.544 x 100
       
(%m/v) = 54.4 g /mL or 54.4% concentration of ammonium carbonate 
                                                solution



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