Verified Answer :

ratio = 1÷1/6 = 6÷1 = 36÷6 = 6

nth term

\(a_{n} = a r^{n-1}\) (where a is the first term)

\(a_{n} = \frac{1}{6} 6^{n-1}\)

Answer:

(6^(n-1))/6

Step-by-step explanation:

The nth term of a geometric series is a function of the number n, the common ratio between each successive number in the series r and the first term a. This may be expressed mathematically as

= a(r)^n-1

Given the series,

a = 1/6,

r = T2/T1 = 1/1/6 = 6

The  nth term

= (1/6)(6)^n-1

= (6^(n-1))/6