The function below shows the number of car owners f(t), in thousands, in a city in different years t:


f(t) = 0.25t2 − 0.5t + 3.5


The average rate of change of f(t) from t = 2 to t = 6 is ______ thousand owners per year.

Verified Answer :

Answer:

1.5 thousand owners per year.

Step-by-step explanation:

Number of car owners is represented by the function as

f(t) = 0.25t² - 0.5t + 3.5

Where 't' is time in years.

Now we have to find the rate of change of f(t) from t = 2 to t = 6

or \(\frac{f(6)-f(2)}{6-2}\)

f(6) = 0.25 × 36 - 0.5 × 6 + 3.5

     = 9 - 3 + 3.5

     = 9.5

f(2) = 0.25 × 4 - 0.5 × 2 + 3.5

     = 1 - 1 + 3.5

     = 3.5

Now average rate of change \(\frac{f(6)-f(2)}{6-2}\)=\(\frac{9.5-3.5}{6-2}\)

\(=\frac{6}{4}\)

= 1.5 thousand owners per year.