Verified Answer :

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tan ⊖ + cot ⊖ = 1/sin⊖cos⊖

sin ⊖ / cos ⊖  + cos ⊖/sin ⊖ = 1/sin⊖cos⊖

(sin ⊖sin ⊖  + cos ⊖cos ⊖)/sin⊖cos⊖ = 1/sin⊖cos⊖

[(sin ⊖)^2 + (cos ⊖)^2 ] /sin⊖cos⊖ = 1/sin⊖cos⊖

1/sin⊖cos⊖ =1/sin⊖cos⊖

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