Verified Answer :

Answer:

The simplified form of given expression\(\frac{15xy}{5x^{\frac{1}{2}}y^2}\) is \(\frac{3x^{\frac{1}{2}}}{y}\)

Step-by-step explanation:

Given: Expression \(\frac{15xy}{5x^{\frac{1}{2}}y^2}\)

We have to write the given expression in simplified form,

Consider the given expression \(\frac{15xy}{5x^{\frac{1}{2}}y^2}\)

Divide the numbers \(\frac{15}{5}=3\)

we get,

\(=\frac{3xy}{y^2x^{\frac{1}{2}}}\)

Apply exponent rule , \(\frac{x^a}{x^b}\:=\:x^{a-b}\)

\(\frac{x}{x^{\frac{1}{2}}}=x^{1-\frac{1}{2}}=x^{\frac{1}{2}}\)

we get,

\(=\frac{3yx^{\frac{1}{2}}}{y^2}\)

Cancel y term, we have,

\(=\frac{3x^{\frac{1}{2}}}{y}\)

Thus, The simplified form of given expression\(\frac{15xy}{5x^{\frac{1}{2}}y^2}\) is \(\frac{3x^{\frac{1}{2}}}{y}\)

Answer:

\(3x^{\frac{1}{2}}y^{-1}\)

Step-by-step explanation:

The given expression is:

\(\frac{15xy}{5x^{\frac{1}{2}}y^2}\)

We have to simplify the above given expression.Thus,

Firstly, divide the constant terms, we get

\(\frac{15}{5}=3\)

Now, applying the exponent law, that is \(\frac{x^a}{x^b}=x^{a-b}\), we have

\(\frac{xy}{x^{\frac{1}{2}}y^2}=x^{1-\frac{1}{2}}y^{1-2}=x^{\frac{1}{2}}y^{-1}\)

Thus, the simplified form of the above given equation is:

\(3x^{\frac{1}{2}}y^{-1}\)