Answered

if the distance between the two objects is tripled how does this affect the overall strength of the electric force between them

Verified Answer :

EjerciciosFyQ

Taking into account the Coulomb's Law: \(F_e = K\cdot \frac{Q_1\cdot Q_2}{d^2}\)

If the value of "d" is tripled:

\(F_e = K\cdot \frac{2Q_1\cdot Q_2}{(3d)^2} = K\cdot \frac{Q_1\cdot Q_2}{9d^2} =\bf \frac{F_e}{9}\)

The new force is nine times smaller.

Related Questions