Verified Answer :

the answer is b1=(2A/h)-b2

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The expression of  b1 in terms of A, h, and b2 is expressed as \(b_1 =\frac{2A}{h} - b_2\)

Given the formula for calculating  the area of a trapezoid expressed as:

\(A = \frac{1}{2}h(b_1+b_2)\)

We are to express b1 in terms of A, h, and b2 as shown

\(A = \frac{1}{2}h(b_1+b_2)\\2A = h(b_1+b_2)\\\frac{2A}{h} = b_1 + b_2\\ b_1 =\frac{2A}{h} - b_2\)

Hence the expression of  b1 in terms of A, h, and b2 is expressed as \(b_1 =\frac{2A}{h} - b_2\)

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