How many moles of CaO are needed to react with an excess of water to form 370 grams of calcium hydroxide?
CaO + H20 --> Ca(OH)2
Calcium Hydroxide has a relative molecular mass of approximately 74 grams. Therefore, with 370 grams provided, we have 370g/74g, or 5 moles.
Therefore, due to molar ratios, 5 moles of CaO must have reacted with 5 moles of H2O to form 5 moles of Ca(OH)2.
The answer to your question is 5 moles of CaO or 280 g of CaO
The required moles of CaO are needed to react with an excess of water to form 370 grams of calcium hydroxide is 280g.
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
Given chemical reaction is:
CaO + H₂O → Ca(OH)₂
Moles of Ca(OH)₂ = 370g / 74g/mol = 5mol
From the stoichiometry of the reaction, 5 moles of CaO is required to produce 5 moles of Ca(OH)₂.
Mass of CaO = (5mol)(56g/mol) = 280g.
Hence required mass of CaO is 280g.
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