The temperature of 15 grams of water increases by 3.0 degress. how much heat was absorbed by water?
Heat = Mass of water specific heat of water temperature rise=
15 g 4.18 J/g K 3K = 188J
The amount of heat absorbed by water is 188.28 J.
we know that, specific heat capacity is the amount of heat required to raise the temperature of 1 g of substance by 1 .0C
C = Q /WΔT
Q= CWΔT
C= specific heat capacity
Q= amount of heat absorbed
W = weight of substance
ΔT = change in temperature
Specific heat capacity of water = 4.18 J/g.0C
Given that,
W = 15 g
ΔT = 3.0C
Q= CWΔT
Q =4.184J/g. 0C15g*3.0C
Q= 188.28 J
Thus, we can conclude that, the amount of heat absorbed by water is 188.28 J.
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