If the average of three numbers is V if one number is Z and another is y what is the remaining number ?
The formula for an average of three numbers is (x+y+z)/3. So if V equals the average, then we find the formula
V = (x+y+z)/3
We are now looking for x. We can divide each of the variables in the parentheses by 3, making the formula
V = x/3 + y/3 + z/3
So now bring the unwanted variables to the same side as V.
V - y/3 - z/3 = x/3
Now multiply both sides by 3 to find x.
3V - y - z = x
x = 3V - y - z
The remaining number, using the concept of average, is \(3V-y-z\)
It is given that
Average of three numbers = V
One number = z
Another number = y
Average is the sum of observations divided by a number of observations.
Let us take the third number x
From the question
\(\frac{x+y+z}{3} = V\)
\(x+y+z = 3V\\\\x=3V-y-z\)
Therefore, the remaining number is \(3V-y-z\)
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