Answered

Which function has real zeros at x = 3 and x = 7?


A- f(x) = x^2 + 4x – 21

B- f(x) = x^2 – 4x – 21

C- f(x) = x^2 – 10x + 21

D- f(x) = x^2 – 10x – 21

Verified Answer :

f(x) = (x - 3)(x - 7)
expanding the brackets gives:
f(x) = x^2 - 10x + 21

abidemiokin

Answer:

f(x) = x² - 10x + 21

Step-by-step explanation:

Functions that has real zeros at x = 3 and x = 7 are the function that produces the roots of 3 and 7 after factorising.

Having two roots as given;

x = 3 and

x = 7

If x=3 then x -3 = 0... 1

Similarly;

If x = 7 then x-7 = 0... 2

Multiplying the zero functions in equation 1 and 2 together we have;

f(x) = (x-3)(x-7)

f(x) = x²-7x-3x+21

f(x) = x² - 10x + 21 = 0

The polynomial or quadratic function above gives the required function.

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