The lines 2y = 3x + 8 and y = 2x + 4 will intersect at (0, 4).
What is the solution to the equation?
The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.
A and B are straight lines.
Line A has equation 2y = 3x + 8 ....1
Line B goes through the points (-1,2) and (2,8). Then the equation of the line will be
y - 2 = [(8 - 2) / (2 + 1)] (x + 1)
y - 2 = 2(x + 1)
y = 2x + 2 + 2
y = 2x + 4 ...2
From equations 1 and 2, then we have
2(2x + 4) = 3x + 8
4x + 8 = 3x + 8
x = 0
Then the value of y will be
y = 2 (0) + 4
y = 4
The lines 2y = 3x + 8 and y = 2x + 4 will intersect at (0, 4).
More about the solution of the equation link is given below.
https://brainly.com/question/545403
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