(3x^-2y)*(8xy^-3) --- SOLVE
1 Use Negative Power Rule: x−a=1xax−a=1xa
3×1x2y×8xy−33×1x2y×8xy−3
2 Use Negative Power Rule: x−a=1xax−a=1xa
3×1x2y×8x×1y33×1x2y×8x×1y3
3 Simplify
24yxx2y324yxx2y3
4 Use Quotient Rule: xaxb=xa−bxaxb=xa−b
24y1−3x1−224y1−3x1−2
5 Simplify 1−31−3 to −2−2
24y−2x1−224y−2x1−2
6 Simplify 1−21−2 to −1−1
24y−2x−124y−2x−1
7 Use Negative Power Rule: x−a=1xax−a=1xa
24×1y2x−124×1y2x−1
8 Use Negative Power Rule: x−a=1xax−a=1xa
24×1y2×1x24×1y2×1x
9 Simplify
24y2x24y2x
\((3x^2-2y)*( 8xy ^{-3} )\)
Remove parentheses : (a) = a
\(= (3x^2-2y) * 8xy ^{-3}\)
\(y^{-3}\)
Apply expoent rule
\(a ^{-b} = \frac{1}{a ^{b} }\)
\(= \frac{1}{y^3}\)
\(8x \frac{1}{y^3} (3x^2-2y)\)
Multiply fractions:
\(a* \frac{b}{c} = \frac{a*b}{c}\)
\(= \frac{8(3x^2-2y)}{y^3}\)
hope this helps!