teisjacklynk
Answered

A ball is thrown straight up. At the top of its path its acceleration is

A0 m/s2.
Babout 5 m/s2.
Cabout 10 m/s2.
Dabout 20 m/s2. E. about 50 m/s2.

Verified Answer :

charleszuker
CAcceleration is the rate of change of velocity. So at the top of the path, while the velocity is zero, the CONSTANT GRAVITATIONAL ACCELERATION is about 10 m/s^2 (9.8)
okpalawalter8

We have that From the Question a ball is thrown straight up. At the top of its path its acceleration is

0 m/s2.

Option A


From the question we are told  

A ball is thrown straight up. At the top of its path its acceleration is

a. 0 m/s2.

b. about 5 m/s2.

c. about 10 m/s2.

d. about 20 m/s2.

E. about 50 m/s2.

Generally

For a Ball thrown straight up at the top of its path where The gravitational force equals the force of the thrown,the Point where the ball is at equilibrium  the Velocity of the ball is zero

Therefore

From the Question

A ball is thrown straight up. At the top of its path its acceleration is

a. 0 m/s2.

Option A


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