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what is the acceleration along the ground of a 10 kg wagon when its pulled with a force of 44 N at an angle of 35° above the horizontal?

A0.23 m/s
B0.28 m/s
C2.52 m/s
D3.60 m/s

Verified Answer :

The correct answer is D I hope this helps you i just took the test and got it right have an amazing day

Answer:

D. 3.60 m/s^2

Explanation:

First of all, we need to find the horizontal force acting on the wagon, which is given by:

\(F_x = F cos \theta=(44 N)(cos 35^{\circ})=36.0 N\)

And now we can calculate the wagon's acceleration by using Newton's second law:

\(a=\frac{F_x}{m}=\frac{36.0 N}{10 kg}=3.60 m/s^2\)