Answer:
A. \(\frac{2}{a-1}\)
Step-by-step explanation:
Given expression is,
\(\frac{2a+2}{a^2-1}\)
\(=\frac{2(a+1)}{a^2-1}\) ( Taking 2 as common from both terms in numerator )
\(=\frac{2(a+1)}{(a+1)(a-1)}\) ( a² - b² = (a+b)(a-b) )
\(=\frac{2}{a-1}\)
Since, the further simplification is not possible,
Hence, option A is correct.
