How do I solve (z+7)^2=3
(z+7)^2=3z^2+14z+46=0z={-14+-√(14^2-4.1.46)}/2.1 =-14+-√(196-184)/2 =-14+-√12/2 =-14+-2√3/2 =-7+-√3so it is,z=-7+√3or, z=-7-√3