In a nuclear reaction a change in mass of 1.0x10^-4 g occurs. what is the corresponding change in energy?
use the formula E=mc^2
You have to convert the mass from g to kg since the unites for a joule is kgm²/s². When you do this you should have E=(1.0×10⁻⁷ kg)×(3.00×10⁸ m/s)². With that E=9.00×10⁹J which equals 9.00×10⁶kJ.
I hope this helps. Let me know if anything is unclear.
The corresponding change in energy is 9 × 10⁶ kJ.
It is expressed as:
E = mc²
where,
E = Energy
m = Mass
c = Speed of light
Convert g into kg
1.0 × 10⁻⁴ g = 1.0 × 10⁻⁴ × 10⁻³
= 1.0 × 10⁻⁷ kg
Now put the value in above formula we get
E = mc²
E = (1.0 × 10⁻⁷ kg) × (3 × 10⁸ ms⁻¹)²
= (1.0 × 10⁻⁷ kg) × (3 × 10⁸ ms⁻¹) × (3 × 10⁸ ms⁻¹)
= (1.0 × 10⁻⁷ kg) × (9 × 10¹⁶ m² s⁻²)
= (9 × 10⁹) kg m² s⁻²
= 9 × 10⁹ J
= 9 × 10⁹ × 10⁻³ [1 Joule = 10⁻³ kJ]
= 9 × 10⁶ kJ
Thus from the above conclusion we can say that The corresponding change in energy is 9 × 10⁶ kJ.
Learn more about the Einstein Equation here: https://brainly.com/question/1603546
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