If A=20 and A= x * (x-1), then?
A= 20A = x(x-1) which means...20 =x(x-1) now solve for x by expanding the brackets,20 = x^2 - x convert this into quadratic equation..x^2 - x - 20 = 0 Factorise >> (x+4)(x-5)hence there could be two values for x x= - 4 or x = 5 Hope this helps!!
We know that A= 20
A= x*(x-1)
20= x(x-1)
20= x^2-x
Subtract x^2 from both sides
20-(x^2-x)= x^2-x-(x^2-x)
-x^2+x+20=0
Factor left sides of equation
(-x-4)(x-5)=0
Set factors equal to 0
-x-4=0 or x-5=0
x = -4 or x= 5
I hope that's help !
