Answer : The mass of KOH needed are, 28 grams
Explanation :
Molarity : It is defined as the number of moles of solute present in one liter of solution.
In this question, the solute is KOH.
Formula used :
\(Molarity=\frac{w_b}{M_b\times V}\times 1000\)
where,
\(w_b\) = mass of solute KOH = ?
\(M_b\) = molar mass of solute KOH = 56 g/mole
V = volume of solution = 250 ml
Molarity = 2.00 M = 2.00 mole/L
Now put all the given values in the above formula, we get the mass of KOH.
\(2.00mole/L=\frac{w_b}{56g/mole\times 250ml}\times 1000\)
\(w_b=28g\)
Therefore, the mass of KOH needed are, 28 grams
