Answer:
\(36\pi cm^2\)
Step-by-step explanation:
We are given that
Volume of cylinder =\(324\pi cm^3\)
Height of cylinder=9 cm
We have to find the area of base of the pillar.
We know that
Volume of cylindrical pillar=\(Base\times Height\)
Where Base=\(\pi r^2\)
Substitute the values then we get
\(324\pi =Base\times 9\)
\(Base=\frac{324\pi}{9}=36\pi cm^2\)
Hence, the area of base of the pillar=\(36\pi cm^2\)
