What is the temperature of 0.80 mol of a gas stored in a 275 mL cylinder at 175 kPa?
PV=nRT (PressureVolume = mol 0,082 (constant) temperature )
175 kPa = 1,727 atm
V=275 ml = 0.275 liters
T=(PV)/(nR)=1,7270.275/0.80.082=7,23 Kelvin.
7.23 K
Data Given:
Moles = n = 0.80 mol
Temperature = T = ??
Pressure = P = 175 kPa = 1.727 atm
Volume = V = 275 mL = 0.275 L
Formula Used:
Let's assume that the gas is acting as an Ideal gas, then according to Ideal Gas Equation,
P V = n R T
where; R = Universal Gas Constant = 0.082057 atm.L.mol⁻¹.K⁻¹
Solving Equation for T,
T = P V / n R
Putting Values,
T = (1.727 atm × 0.275 L) ÷ (0.80 mol × 0.082057 atm.L.mol⁻¹.K⁻¹)
T = 7.23 K