George just bought a new scooter for $8000. He plans on keeping it until it is worth a fourth of it's original price.


He believes that every year the scooter loses an eighth of its value. He can represent the value of the scooter by the equation V = 8000(7/8)t, where V is the value of the scooter and t is the number of years that have passed.


As he was leaving the dealership he was told that the scooter really loses a sixth of it's value every year. What should George change in the equation V = 8000(7/8)t to represent this new situation?


AReplace the 7/8 with a 6.
BReplace the 8000 with 5/6.
CSwitch the V and t
DReplace the 7/8 with a 5/6.

Verified Answer :

since it's 1/6th and not 1/8th then replace 7/8 with a 5/6

Answer:

D) Replace the 7/8 with a 5/6.

Step-by-step explanation:

Given,

The original value of the scooter = $ 8000,

If it loses an eighth of its value.

Then the decrement in the price of scooter = \(\frac{1}{8}\) of the original price of the scooter

\(=\frac{1}{8}\times 8000\)

\(=\frac{8000}{8}\)

Now, the final price of the scooter = Original price of the scooter - Decrement in price

\(=8000-\frac{8000}{8}\)

\(=8000(1-\frac{1}{8})\)

\(=8000(\frac{8-1}{8}\)

\(=8000(\frac{7}{8})\)

Similarly, If it loses an sixth of its value.

Then, decrement in price = \(\frac{1}{6}\) of 8000

\(=\frac{8000}{6}\)

And, the final price of the scooter = \(8000-\frac{8000}{6}\)

\(=8000(1-\frac{1}{6})\)

\(=8000(\frac{6-1}{6})\)

\(=8000(\frac{5}{6})\)

Hence, Option D is correct.