Solve the system of equations 3r – 4s = 0 and 2r + 5s = 23
\(3r-4s=0\)
\(3r=4s\)
\(r=\frac{4}{3}s\)
\(2r+5s=23\)
\(2(\frac{4}{3}s)+5s=23\)
\(\frac{8}{3}s+5s=23\)
\(5\frac{8}{3}s=23\)
\(s=3\)
\(3r-4s=0\)
\(3r-4(3)=0\)
\(3r=12\)
\(r=4\)
s=3, r=4
Check:
\(2r+5s=23\)
\(2(4)+5(3)=23\)
\(8+15=23\)
\(23=23\) CHECK