AThe answer is 0.1.
The frequency of IA allele is 0.2:
IA = 0.2
The frequency of O individuals is 0.49:
ii = 0.49
Since there is only one possible genotype for O individuals - ii - the frequency of i is square root of the frequency of O individuals:
i = √ii
⇒ i = √0.49
⇒ i = 0.7
Now, we have the frequencies of two alleles (IA and i). To calculate the frequency of IB allele, we will use the formula:
IA + i + IB = 1
⇒ IB = 1 - IA - i
⇒ IB = 1 - 0.2 - 0.7
⇒ IB = 0.1
So, the frequency of IB allele is 0.1.
b) The answer is 0.32.
There are two possible genotypes for A individuals - \(I^{A} I^{A}\) and \(I^{A}i\).
Frequency of \(I^{A} I^{A}\) is:
\(I^{A} I^{A}\) = AI² = 0.2² = 0.04
Frequency of \(I^{A}i\) is:
\(I^{A}i\) = 2 x AI x i = 2 x 0.2 x 0.7 = 0.28
Frequency of people with type A blood is the sum of these two frequencies:
A = 0.04 + 0.28 = 0.32
The number of people with type A blood would be:
0.32 x 1000 people = 320 people