A landscaper is creating a rectangular flower bed such that the width is half of the length.The area of the flower that is 34 ft.² Write an equation to determine the width of the flower bed to the nearest tenth of a foot
The Area is \(A=l * w\) and we know that \(w=\frac{l}{2}\)
Therefore: \(34=l * \frac{l}{2} = \frac{l^{2}}{2}\)
\(68=l^{2}\)
\(\sqrt{68}=l=8.246\)
and thus:
\(w=\frac{8.246}{2}\)
\(w=4.123\)
round to nearest tenth:
\(w=4.1feet\)
area=LW
W=L/2
2W=L
A=34
sub 34 for A and 2W for L
34=(2W)W
34=2W^2
divide 2
17=W^2
square root both sides
4.12=W
round tenth
4.1 ft=W