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When Sharon begin shopping this morning, she have $40. she purchased 5 paperback books and had lunch. The books were all the same price and lunch cost $3.25 she now has $7 left over what was the price of each book

A8.75
B5.95

c.6.60

d.7.35

Verified Answer :

twvogels

Call the price of a book 'b'. We know that lunch cost $3.25 so let's say @@MATH_TOKEN_0@@ we also know the total is $40. So we can write: 
\(T=L+5b+7\)
or
\(40=3.25+5b+7\) 
and then solve for 'b':
\(29.75=5b\)
\(b=\frac{29.75}{5} = 5.95\)

A book cost $5.95

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