what s the factor of (x+3)(x+2)
Simplifying
(x + 3)(x + 2)
Reorder the terms:
(3 + x)(x + 2)
Reorder the terms:
(3 + x)(2 + x)
Multiply (3 + x) (2 + x)
(3(2 + x) + x(2 + x))
((2 3 + x 3) + x(2 + x))
((6 + 3x) + x(2 + x))
(6 + 3x + (2 x + x * x))
(6 + 3x + (2x + x2))
Combine like terms: 3x + 2x = 5x
(6 + 5x + x2)
Factor a trinomial.
(3 + x)(2 + x)
Final result:
(3 + x)(2 + x)
Basically, don't listen to the other guy, he is making up random stuff, report him.
You can solve this just by multiplying by FOIL
Firsts
Outsides
Insides
Lasts
The firsts of (x+3)(x+2) are x and x, so xx = x^2
The outsides of (x+3)(x+2) are x and 2, so x2 = 2x
The insides of (x+3)(x+2) are 3 and x, so 3x = 3x
The lasts of (x+3)(x+2) are 3 and 2, so 32 = 6
Add of of that together, x^2 + 2x + 3x + 6
So the answer is: x^2 + 5x + 6