Verified Answer :

apologiabiology

x=y+7
subsitute y+7 for x since they are equal

3(y+7)+2y=96
distribute
3y+21+2y=96
add like terms
5y+21=96
minus 21 from both sides
5y=75
divide both sides by 5
y=15

sub
x=y+7
x=15+7
x=22


solution where you have (x,y)
(22,15)

krupa

At first we should plug the value of x in the second equation.

3(y+7) +2y = 96

3y +21 +2y = 96

5y =96-21

5y= 75

y = 15

Then we should find the value of x.For that we should plug the value of y in 1rst equation.

x = y+7

x= 15+7

x = 22.

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