Charge q is 1 unit of distance away from the source charge S. Charge p is four times further away. The force exerted between S and q is _____ the force exerted between S and p.

one0fourth

four times

one0sixteenth

sixteen times

Verified Answer :

The correct answer is:

sixteen times


In fact, the distance between charge q and the source S is 1 unit. Instead, the distance between charge p and the source S is 4 units. The magnitude of the electrostatic force is inversely proportional to the square of the distance between the charge and the source:

\(E \sim \frac{1}{r^2}\)

where r is the distance. If we take the force between q and S as reference, we have r=1, so that

\(E_{qS}=\frac{1}{1^2}=1\)

while the force between p and S is

\(E_{pS}=\frac{1}{4^2}=\frac{1}{16}\)

Therefore, we see that the force exerted between q and S is 16 times the force exerted between p and S.