Which shows 23^2017^2 being evaluated using the difference of perfect squares method?
A.23^3017^2=(529+289)(5290289)=196,320
B.23^2017^2=5290289=240
C.23^2017^2=(23+17)(23017)=(40)(6)=240
D.23^2017^2=(23017)^2=(6)^2=36
A.23^3017^2=(529+289)(5290289)=196,320
B.23^2017^2=5290289=240
C.23^2017^2=(23+17)(23017)=(40)(6)=240
D.23^2017^2=(23017)^2=(6)^2=36